x^2+0.18x-0.018=0

Solution for x^2+0.18x-0.018=0 equation:

x^2+0.18x-0.018=0

a = 1; b = 0.18; c = -0.018;
Δ = b2-4ac
Δ = 0.182-4·1·(-0.018)
Δ = 0.1044
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.18)-\sqrt{0.1044}}{2*1}=\frac{-0.18-\sqrt{0.1044}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.18)+\sqrt{0.1044}}{2*1}=\frac{-0.18+\sqrt{0.1044}}{2}
$